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X^2-2X-4096=0
a = 1; b = -2; c = -4096;
Δ = b2-4ac
Δ = -22-4·1·(-4096)
Δ = 16388
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{16388}=\sqrt{4*4097}=\sqrt{4}*\sqrt{4097}=2\sqrt{4097}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{4097}}{2*1}=\frac{2-2\sqrt{4097}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{4097}}{2*1}=\frac{2+2\sqrt{4097}}{2} $
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